From: Bart Schaefer <schaefer@brasslantern.com>
To: zsh-users@sunsite.dk
Subject: Re: passing parameters
Date: Fri, 06 May 2005 16:03:22 +0000 [thread overview]
Message-ID: <1050506160323.ZM32155@candle.brasslantern.com> (raw)
In-Reply-To: <h8pm71l1hhufkpk2s2kkl4apejpmph0mr3@4ax.com>
On May 6, 1:54pm, zzapper wrote:
>
> cnt=$(ls **/*.tex |egrep -ic "$1[^/]*.tex" )
> texfile=$(ls **/*.tex |egrep -i "$1[^/]*.tex" )
[versus]
> param="$1.*$2"
> cnt=$(ls **/*.tex |egrep -ic "${param}[^/]*.tex" )
> texfile=$(ls **/*.tex |egrep -i "${param}[^/]*.tex" )
>
> But why is it necessary to write ${param} ? and it wasn't necessary to
> write ${1}
$identifier[subscript] is an array expression. When $identifier is a
scalar, it does character-wise indexing to extract substrings.
"1" is not an identifier. $1 is a special case of expansion used for
the positional parameters. So $1[anything] is not an array expression,
it's the expression $1 followed by the string [anything]. Similarly,
$1foo is ${1}foo because "1foo" is not an identifier, but "foo1" is an
identifier so $foo1 is the same as ${foo1}.
You can force indexing into $1 by ${1[subscript]}.
prev parent reply other threads:[~2005-05-06 16:03 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2005-05-05 21:42 zzapper
2005-05-06 3:57 ` Bart Schaefer
2005-05-06 12:54 ` zzapper
2005-05-06 16:03 ` Bart Schaefer [this message]
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