Re: outputs of _users and _hosts to arrays

[Motoi Washida <a66@h8.dion.ne.jp>]

Hi Wataru,

On 07/25/2005, at 14:18, Wataru Kagawa wrote:

> Hi Bart,
>
> Thanks for the help.
> After googling, I found out that _users extract usernames from /etc/ 
> passwd and _hosts extract hostnames from /etc/hosts.
>
> So, I can use parameter expansions like,
>
> users=( ${$( cat /etc/users | cut -d : -f 1,7 | grep -v "#" )//:*/} )
If you do that on Mac OS X, maybe you can't get even your name. ;-)
The more general way is using $userdirs special variable.

Load zsh/parameter module,

% zmodload -i zsh/parameter

and,

% users=( $userdir[(I)*] )


I think you can also get user names by calling hash builtin function.  
But I had to rebuild named directory hash table to get expected  
results on some platforms.

You might need to call this,

% builtin hash -fd

and get hash table entries,

% users=( ${${(f)"$(builtin hash -d)"}%\=*} )

> hosts=( ${$( cat /etc/hosts | cut -d : -f 1,7 | grep -v "#" )//:*/} )
>
> to get what I need.
This has the same problem, but I don't know a better way well. Using  
some functions from Perl or some other language?