From mboxrd@z Thu Jan  1 00:00:00 1970
Return-Path: <zsh-users-return-15899-mason-zsh=primenet.com.au@zsh.org>
Received: (qmail 24768 invoked by alias); 25 Mar 2011 22:04:18 -0000
Mailing-List: contact zsh-users-help@zsh.org; run by ezmlm
Precedence: bulk
X-No-Archive: yes
List-Id: Zsh Users List <zsh-users.zsh.org>
List-Post: <mailto:zsh-users@zsh.org>
List-Help: <mailto:zsh-users-help@zsh.org>
X-Seq: 15899
Received: (qmail 8094 invoked from network); 25 Mar 2011 22:04:16 -0000
X-Spam-Checker-Version: SpamAssassin 3.3.1 (2010-03-16) on f.primenet.com.au
X-Spam-Level: 
X-Spam-Status: No, score=-1.9 required=5.0 tests=BAYES_00,RCVD_IN_DNSWL_NONE
	autolearn=ham version=3.3.1
Received-SPF: none (ns1.primenet.com.au: domain at closedmail.com does not designate permitted sender hosts)
From: Bart Schaefer <schaefer@brasslantern.com>
Message-id: <110325150350.ZM30913@torch.brasslantern.com>
Date: Fri, 25 Mar 2011 15:03:49 -0700
In-reply-to: <9861b13e6828d43041a5b489f016664a.squirrel@gameframe.net>
Comments: In reply to nix@myproxylists.com
 "How to add string to end of each array element without loops" (Mar 25,
 11:32pm)
References: <9861b13e6828d43041a5b489f016664a.squirrel@gameframe.net>
X-Mailer: OpenZMail Classic (0.9.2 24April2005)
To: zsh-users@zsh.org
Subject: Re: How to add string to end of each array element without loops
MIME-version: 1.0
Content-type: text/plain; charset=us-ascii

On Mar 25, 11:32pm, nix@myproxylists.com wrote:
} Subject: How to add string to end of each array element without loops
}
} a=(1 2 3)
} a=(foo$^a[@])
} 
} print -l "${(@n)a}"

If $^a[@] works, then you don't need the subscript, either:

a=(foo$^a)

Futhermore you don't need the quotes and (@) in the print expression:

print -l ${(n)a}

} foo1
} foo2
} foo3
} 
} I would like to get the following output instead:
} 
} 1foo
} 2foo
} 3foo

I'm not understanding what you're asking.  Either this is as easy as

    a=(1 2 3)
    a=(${^a}foo)  # braces needed to distinguish $a from $afoo

or you've already got (foo$^a) and you're asking how to change "foo?"
into "?foo" for the whole array

    setopt extendedglob
    a=(${a/(#b)foo(<->)/$match[1]foo})

or you mean something else entirely.  Can you elaborate?

--