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From: Bart Schaefer <schaefer@brasslantern.com>
Message-id: <110902100313.ZM8455@torch.brasslantern.com>
Date: Fri, 02 Sep 2011 10:03:13 -0700
In-reply-to: <Xns9F54A6DEAC33Bzzappergmailcom@80.91.229.10>
Comments: In reply to zzapper <david@tvis.co.uk>
 "listing sub-drectories with most files in" (Sep  2,  3:24pm)
References: <Xns9F54A6DEAC33Bzzappergmailcom@80.91.229.10>
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To: zsh-users@zsh.org
Subject: Re: listing sub-drectories with most files in
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On Sep 2,  3:24pm, zzapper wrote:
}
} I'm grepping a tree (grep string **/*) and want to list the
} subdirectories which have the most files. This is because the grep is
} taking ages and I'm hoping I can exclude some of these.

This will give you the directories and the count of files in each,
in ascending order by number of files:

print **/*(/ne{'reply=($REPLY/*(N.)); reply=($#reply\:$REPLY)'})

I'll leave it up to you to decide how you want to make use of that
information.