From: Bart Schaefer <schaefer@brasslantern.com>
To: zsh-users@zsh.org
Subject: Re: listing sub-drectories with most files in
Date: Sat, 10 Sep 2011 12:37:29 -0700 [thread overview]
Message-ID: <110910123729.ZM18232@torch.brasslantern.com> (raw)
In-Reply-To: <DC1CE18A-7E0E-4CF9-8D86-52B155C5FE0C@gmail.com>
On Sep 10, 1:53pm, Aaron Davies wrote:
}
} (for d (**/*(/)) echo `ls $d|wc -l` $d)|sort -n
These are all good tries, but `ls $d` will include subdirectory names
as well as file names; the original request was for a count of files.
Further you have to worry whether there's an alias for "ls" that may
change it from listing one file per line.
If you use `print -l $d/*(N.)` you fix both of these problems, but
you're still forking `wc -l`. Try ${#$(print -l $d/*(.))} ?
Replace ( ... ) with { ... } to avoid unnecessary subshells:
{ for d (**/*(/)) print ${#$(print -l $d/*(.))} $d } | sort -n
On my desktop that's 10x faster than using `ls|wc` but still 2x slower
than my all-globbing solution. OTOH the all-globbing solution might
take 5x as long to type. :-)
prev parent reply other threads:[~2011-09-10 19:37 UTC|newest]
Thread overview: 11+ messages / expand[flat|nested] mbox.gz Atom feed top
2011-09-02 15:24 zzapper
2011-09-02 17:03 ` Bart Schaefer
2011-09-02 18:30 ` zzapper
2011-09-02 18:59 ` Bart Schaefer
2011-09-03 12:02 ` Thor Andreassen
2011-09-03 15:13 ` Bart Schaefer
2011-09-03 19:23 ` Thor Andreassen
2011-09-03 21:59 ` Bart Schaefer
2011-09-04 0:34 ` Thor Andreassen
2011-09-10 17:53 ` Aaron Davies
2011-09-10 19:37 ` Bart Schaefer [this message]
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