From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 22768 invoked by alias); 15 Oct 2011 06:57:04 -0000 Mailing-List: contact zsh-users-help@zsh.org; run by ezmlm Precedence: bulk X-No-Archive: yes List-Id: Zsh Users List List-Post: List-Help: X-Seq: 16487 Received: (qmail 26260 invoked from network); 15 Oct 2011 06:57:02 -0000 X-Spam-Checker-Version: SpamAssassin 3.3.1 (2010-03-16) on f.primenet.com.au X-Spam-Level: X-Spam-Status: No, score=-1.9 required=5.0 tests=BAYES_00,RCVD_IN_DNSWL_NONE autolearn=ham version=3.3.1 Received-SPF: none (ns1.primenet.com.au: domain at closedmail.com does not designate permitted sender hosts) From: Bart Schaefer Message-id: <111014235652.ZM10877@torch.brasslantern.com> Date: Fri, 14 Oct 2011 23:56:52 -0700 In-reply-to: <20111015062430.GA3088@solfire> Comments: In reply to meino.cramer@gmx.de "replacing a textual part of all parameters in a cmd line" (Oct 15, 8:24am) References: <20111015062430.GA3088@solfire> X-Mailer: OpenZMail Classic (0.9.2 24April2005) To: zsh-users@zsh.org Subject: Re: replacing a textual part of all parameters in a cmd line MIME-version: 1.0 Content-type: text/plain; charset=us-ascii On Oct 15, 8:24am, meino.cramer@gmx.de wrote: } } !30007:s/front/side1/g } } which gaves me the same result as above. Actually if you looked closely I think you'd find that it gave you the result as before except with a "g" added at the end. } What is the correct command to change all parameters of the command } line as described above? You put the g at the front. !30007:gs/front/side1/