Re: Could you provide bash's \$ which like zsh %#?

[Bart Schaefer <schaefer@brasslantern.com>]

On Dec 7,  1:03pm, Daniel Lin wrote:
} Subject: Re: Could you provide bash's \$ which like zsh %#?
} 
} Sorry, I've tried, it display strange things.
} PS1='%# %(#,$,%%)'

That was Josh's attempt to give you one example that shows both %#
and a conditional string that displays something not quite the same,
so that you could compare the two.  It was not intended to be the
prompt that you would use, just a sample of what could be done.

On Dec 7,  3:04pm, Daniel Lin wrote:
} Subject: Re: Could you provide bash's \$ which like zsh %#?
}
} So, to match the document, I should change the prompt to
} PS1='%(!.#.$)'

Yes, almost.  You probably want the trailing space in there.

PS1='%(!.#.$) '

Equivalently, %(#,#,$) says "if the UID is zero, pound, else dollar"
"Running with privileges" could mean something other than "running as
the root user" in obscure circumstances.  %(#,,) is the generalized
form of %(!,,), so that you can test for explicit UID; the default
when no UID is given is zero.  So another possible example is

PS1='%(2#,Running as daemon ,)%(!.#.$) '

[Assuming that UID 2 is "daemon" as it is on my Linux box.]