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From: ZyX <kp-pav@yandex.ru>
To: Eric Cook <llua@gmx.com>,
	"zsh-users@zsh.org" <zsh-users@zsh.org>
In-Reply-To: <1102431421682670@web6h.yandex.ru>
References: <CADdV=MvMtwYczr82GeYkmVwTFCKgFcbgYS71XdnHZN_JqFqzTg@mail.gmail.com> <54BC1B8E.5080806@gmx.com> <1102431421682670@web6h.yandex.ru>
Subject: Re: Equivalent of set -- *(DN) in sh
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Date: Mon, 19 Jan 2015 18:55:21 +0300
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19.01.2015, 18:51, "ZyX" <kp-pav@yandex.ru>:
> 18.01.2015, 23:53, "Eric Cook" <llua@gmx.com>:
>>  On 01/18/2015 01:28 PM, Nikolai Weibull wrote:
>>>   Hi!
>>>
>>>   Is there any way to get the equivalent of Zsh’s
>>>
>>>   set -- *(DN)
>>>
>>>   in sh?  Most important here would be NULL_GLOB, as, by default, sh
>>>   simply leaves the * if there are no files to match.
>>>
>>>   Thanks!
>>  match() {
>>    test "$#" -gt 2 && return
>>    test -e "$1"    && return
>>    return 1
>>  }
>>
>>  set --
>>  for pat in '.[^.]*' '*'; do # *(DN) ignores . and ..
>
> `..foo` is a valid name, but it is being excluded. You need to add `'.??*'` to the list of patterns.

No, this may make duplicates. Then `'..?*'`.

>>    if match $pat; then
>>      set -- "$@" $pat
>>    fi
>>  done
>>  unset pat
>>
>>  test "$#" -gt 0 && printf '%s\n' "$@"