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From: Bart Schaefer <schaefer@brasslantern.com>
Message-id: <120306230111.ZM11639@torch.brasslantern.com>
Date: Tue, 06 Mar 2012 23:01:11 -0800
In-reply-to: <1331054185.27052.19.camel@air.fifi.org>
Comments: In reply to Philippe Troin <phil@fifi.org>
 "Re: Is it possible to capture stdout and stderr to separate variables in
 Zsh?" (Mar  6,  9:16am)
References:
 <CADdV=Mtbszh2NjtB8yFjfeo9PR1U7XV-Qi2AQMXCZ0Ag0VTS+w@mail.gmail.com>
	<1331054185.27052.19.camel@air.fifi.org>
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To: Zsh Users <zsh-users@zsh.org>
Subject: Re: Is it possible to capture stdout and stderr to separate variables
 in Zsh?
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On Mar 6,  9:16am, Philippe Troin wrote:
}
} On Tue, 2012-03-06 at 09:09 +0100, Nikolai Weibull wrote:
} > Is it possible to capture stdout and stderr to separate variables in Zsh?
} 
} All I can think of is:
} 
}         coproc cat &
}         pid=$!
}         stdout="$( ( print "printed on stdout"; print -u 2 "printer on stderr" ) 2>&p )"
}         sleep 1 
}         kill "$pid"
}         stderr="$(cat <&p)"
} 
} You'll notice the very ugly sleep+kill hack I had to use as I could not
} find how you can close a coprocess's standard input cleanly.  Removing
} the sleep+kill makes the cat <&p hang forever.

You need this:  http://www.zsh.org/mla/users/2011/msg00095.html  :-)

} A completely different solution could involve the tcp zsh module which
} can multiplex many streams with tcp_expect.  But that's probably too
} involved for this problem.

You might also be able to do something with the zsh/zselect module, but
just use a temp file.  That solution works in bash, too.