From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 19584 invoked by alias); 19 Oct 2012 15:38:48 -0000 Mailing-List: contact zsh-users-help@zsh.org; run by ezmlm Precedence: bulk X-No-Archive: yes List-Id: Zsh Users List List-Post: List-Help: X-Seq: 17335 Received: (qmail 22463 invoked from network); 19 Oct 2012 15:38:45 -0000 X-Spam-Checker-Version: SpamAssassin 3.3.2 (2011-06-06) on f.primenet.com.au X-Spam-Level: X-Spam-Status: No, score=-1.9 required=5.0 tests=BAYES_00,RCVD_IN_DNSWL_NONE autolearn=ham version=3.3.2 Received-SPF: none (ns1.primenet.com.au: domain at closedmail.com does not designate permitted sender hosts) From: Bart Schaefer Message-id: <121019083818.ZM3914@torch.brasslantern.com> Date: Fri, 19 Oct 2012 08:38:18 -0700 In-reply-to: <20121019080315.GB6056@localhost.localdomain> Comments: In reply to Han Pingtian "flag z won't cause forced joining?" (Oct 19, 4:03pm) References: <20121019080315.GB6056@localhost.localdomain> X-Mailer: OpenZMail Classic (0.9.2 24April2005) To: zsh-user Subject: Re: flag z won't cause forced joining? MIME-version: 1.0 Content-type: text/plain; charset=us-ascii On Oct 19, 4:03pm, Han Pingtian wrote: } } I just found that it looks like the z flag won't cause "forced joining" } which stated in rules 10 Yes, this is a case of the documentation being wrong; it was recently corrected. Rule 10 now says: 10. _Forced joining_ If the `(j)' flag is present, or no `(j)' flag is present but the string is to be split as given by rule 11., and joining did not take place at step 5., any words in the value are joined together using the given string or the first character of $IFS if none. Note that the `(F)' flag implicitly supplies a string for joining in this manner. 11. _Simple word splitting_ If one of the `(s)' or `(f)' flags are present, or the `=' specifier was present (e.g. ${=VAR}), the word is split on occurrences of the specified string, or (for = with neither of the two flags present) any of the characters in $IFS. If no `(s)', `(f)' or `=' was given, but the word is not quoted and the option SH_WORD_SPLIT is set, the word is split on occurrences of any of the characters in $IFS. Note this step, too, takes place at all levels of a nested substitution. Note that the reference to rule 17 [the (z) flag] has been removed from rule 10 (and rule 11 is new).