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From: Bart Schaefer <schaefer@brasslantern.com>
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Date: Tue, 05 Aug 2014 08:55:27 -0700
In-reply-to: <20140805054434.GA4390@linux.vnet.ibm.com>
Comments: In reply to Dominik Vogt <vogt@linux.vnet.ibm.com>
 "copying an array" (Aug  5,  6:44am)
References: <20140805054434.GA4390@linux.vnet.ibm.com>
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To: vogt@linux.vnet.ibm.com, Zsh Users <zsh-users@zsh.org>
Subject: Re: copying an array
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On Aug 5,  6:44am, Dominik Vogt wrote:
>
> typeset -g -a G
> G=("a b c" d e)
> copy_array () {
> 	typeset -g -a "$1"
> 	# how can this be done?
> 	$1="($G[@])"
> }

You probably don't need the function at all if this is the only thing it
is doing:

	set -A "$1" "$G[@]"

The only reason for the "typeset -g" would be if there is a local array
in scope whose name is the same as the value of $1.  Otherwise "set -A"
will create the global array for you.