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From: Ronald Fischer <ynnor@mm.st>
To: "Zsh Mailing-List" <zsh-users@zsh.org>
Subject: Possible bug: Zsh function does not terminate when ${name:?word} fails
Date: Wed, 14 Sep 2016 10:00:44 +0200	[thread overview]
Message-ID: <1473840044.77968.725190513.460F8572@webmail.messagingengine.com> (raw)

(See also for a complete discussion:
http://stackoverflow.com/questions/39463547/zsh-function-does-not-terminate-when-nameword-fails?noredirect=1#comment66276136_39463547)

I have in my .zshrc the following function definition (simplified
example):

function foo {
  local p=${1:?parameter missing}
  echo continue ....
}

Running the function by just typing foo produces, as expected, the
message parameter missing, but it also outputs continue. I had expected
that the function terminates when the :? check fails, but it continues
to run.

I tested this with zsh 5.1.1, but I was informed that this behaviour
also can be reproduced with zsh 5.2

Ronald


             reply	other threads:[~2016-09-14  8:00 UTC|newest]

Thread overview: 6+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
     [not found] <CGME20160914080154eucas1p11c49e4dd5f0d45f92deaef1ce08099de@eucas1p1.samsung.com>
2016-09-14  8:00 ` Ronald Fischer [this message]
2016-09-14  8:19   ` Mikael Magnusson
2016-09-14 11:21     ` Ronald Fischer
2016-09-14 16:20       ` Bart Schaefer
2016-09-14 19:08         ` Mikael Magnusson
2016-09-14  9:19   ` Peter Stephenson

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