From: Bart Schaefer <schaefer@brasslantern.com>
To: zsh-users@zsh.org
Subject: Re: Global And Local Variables in zsh Functions
Date: Sat, 8 Aug 2015 17:31:47 -0700 [thread overview]
Message-ID: <150808173147.ZM14125@torch.brasslantern.com> (raw)
In-Reply-To: <55C68669.8000408@netcologne.de>
On Aug 9, 12:44am, Georg Wittig wrote:
}
} x1=$(my_f2 /tmp)
} x2=$(my_f2 /opt/windows7)
}
} To my surprise, EXC is empty now:
}
} Why is EXC empty in the case of my_f2, and correct in the case my_f1?
The use of $(...) means your my_f2 function runs in a forked child process,
and so changes to variables are not visible to the parent shell. If you
want my_f2 to work like my_f1, you'll have to do something like
function my_f2 () {
EXC+=" --exclude='$1'";
typeset -g $2="some value depending on $1"
}
my_f2 /tmp x1
my_f2 /opt/windows7 x2
next prev parent reply other threads:[~2015-08-09 0:31 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2015-08-08 22:44 Georg Wittig
2015-08-09 0:26 ` ZyX
2015-08-09 0:31 ` Bart Schaefer [this message]
2015-08-09 0:45 ` Mikael Magnusson
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