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From: Bart Schaefer <schaefer@brasslantern.com>
Message-Id: <150808173147.ZM14125@torch.brasslantern.com>
Date: Sat, 8 Aug 2015 17:31:47 -0700
In-Reply-To: <55C68669.8000408@netcologne.de>
Comments: In reply to Georg Wittig <nc-wittigge@netcologne.de>
        "Global And Local Variables in zsh Functions" (Aug  9, 12:44am)
References: <55C68669.8000408@netcologne.de>
X-Mailer: OpenZMail Classic (0.9.2 24April2005)
To: zsh-users@zsh.org
Subject: Re: Global And Local Variables in zsh Functions
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On Aug 9, 12:44am, Georg Wittig wrote:
}
} x1=$(my_f2 /tmp)
} x2=$(my_f2 /opt/windows7)
} 
} To my surprise, EXC is empty now:
} 
} Why is EXC empty in the case of my_f2, and correct in the case my_f1?

The use of $(...) means your my_f2 function runs in a forked child process,
and so changes to variables are not visible to the parent shell.  If you
want my_f2 to work like my_f1, you'll have to do something like

function my_f2 () {
    EXC+=" --exclude='$1'";
    typeset -g $2="some value depending on $1"
}

my_f2 /tmp x1
my_f2 /opt/windows7 x2