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From: Bart Schaefer <schaefer@brasslantern.com>
Message-Id: <160908090800.ZM13466@torch.brasslantern.com>
Date: Thu, 8 Sep 2016 09:08:00 -0700
In-Reply-To: <CAKc7PVApZGBAoQ4GywTLzbJXmNOrq2-W_iP7p+ifWqzYF49N+g@mail.gmail.com>
Comments: In reply to Sebastian Gniazdowski <sgniazdowski@gmail.com>
        "Fastest way to count # of files?" (Sep  8,  5:36pm)
References: <CAKc7PVApZGBAoQ4GywTLzbJXmNOrq2-W_iP7p+ifWqzYF49N+g@mail.gmail.com>
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To: Zsh Users <zsh-users@zsh.org>
Subject: Re: Fastest way to count # of files?
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On Sep 8,  5:36pm, Sebastian Gniazdowski wrote:
}
} [...]  The second code reads the whole directory too, but
} it's slow. First code doesn't provide way to determine # of files
} read. Is there anything between these two? Something that doesn't
} store files, but counts them?

Try this:

  integer nfiles=0
  : **/*(Ne?'((++nfiles)) && reply=()'?)
  print $nfiles