Re: Problems running echo -e in a variable

["Thomas Köhler" <jean-luc@picard.franken.de>]

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On Wed, Feb 14, 2001 at 09:00:39PM +0100,
Heinrich Götzger <goetzger@gmx.net> wrote:
> 
> Hi there,
> 
> I' ve got 2 questions using zsh as shell-script interpreter. To track it
> more easily, I'm splitting it in 2 different mails.
> 
> Running zsh version 3.1.6 included in SuSE Linux 7.0 I got some trouble
> using "echo -e" in a variable:
> 
> $ echo -e "Hallo Heinrich"
> Hallo Heinrich
> 
> is ok, but:

Of course it is :-)

> $ ECHO="echo -e"
> $ $ECHO "Hallo Heinrich"
> zsh: command not found: echo -e

So, zsh doesn't split $ECHO.

> also with {} it brings the same:
> $ ${ECHO} Hallo Heinrich
> zsh: command not found: echo -e

Of course, ${ECHO} is basically the same as $ECHO :-)

> How can I avoid this?
> 
> I've seen it working with ksh or bash.

setopt sh_word_split
:-)

> Regards and thanks for the help
> 
> Heinrich Götzger

Ciao,
Thomas

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