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Date: Fri, 8 Feb 2002 16:55:36 -0700
From: Steve Talley <stephen.talley@sun.com>
To: Bart Schaefer <schaefer@brasslantern.com>
Cc: zsh-users@sunsite.dk
Subject: Re: Reverse the order of an array?
Message-ID: <20020208165535.D10334@thpppt>
References: <20020208153514.C10334@thpppt> <Pine.BSF.4.40.0202082239301.90676-100000@brasslantern.com>
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In-Reply-To: <Pine.BSF.4.40.0202082239301.90676-100000@brasslantern.com>; from schaefer@brasslantern.com on Fri, Feb 08, 2002 at 10:59:37PM +0000

Thanks Bart.  The best that I had come up with was:

    indexes=({$#osvers..1})
    tmp=('$osvers['$^indexes']')
    osvers=${(e)tmp}

Do you see any way (other than skipping the whole thing :) to simplify
this?

Thanks,

Steve

Bart Schaefer wrote:

> On Fri, 8 Feb 2002, Steve Talley wrote:
> 
> > How can I easily reverse the order of an array in zsh?
> 
> Depends what you mean by "easily."
> 
> > I was hoping that something like
> >
> >     osvers=($osvers[{$#osvers..1}])
> >
> > would work, but no luck.
> 
> Array "slices" in zsh only have start and end points, and are always in
> ascending order by numeric position in the array.  So you can't do this
> purely with parameter expansion in the general case.
> 
> This works:
> 
> for ((i=$#osvers; i>0; --i)) { osvers[i*2]=($osvers[1]); shift osvers }