Re: insert-last-word/copy-prev-word/... question

[Dominik Vogt <dominik.vogt@gmx.de>]

On Wed, Mar 06, 2002 at 11:22:57AM +0100, poeml@cmdline.net wrote:
> On Fri, Mar 01, 2002 at 03:33:13 +0100, Dominik Vogt wrote:
> > Let's assume I have this in the history
> > 
> >   ls xxx xxx foo
> >   ls xxx xxx bar
> >   ls yyy zzz baz
> > 
> > And I'm typing a new command line:
> > 
> >   $ ls first second next 
> >                          ^
> >                          cursor
> > 
> > with insert-last word, I can copy "baz", "bar", "foo" to the
> > cursor position.  With copy-prev-word I can copy "next".  But I'd
> > like to
> > 
> >  - Call some function multiple times.  With the first call I get
> >    "next".  WIth the second call I get "second" and with the
> >    third call I get "first".
> >  - The same should work on previous lines in the history:  First I
> >    call insert-last and get "baz", then I call said function and
> >    get "zzz", then I call it again and get "yyy".
> > 
> > Is that possible?
> 
> How about simply prefixing insert-last with a multiplier, is that what
> you want (not sure if I understand correctly)? 
> 
> Like "meta-2 meta-." which would give you "zzz" in you example. 

Ah, yes.  I guess you have to already know what the argument to
insert-last-word does to understand the man page :-)  Now, is
there a way to call that with increasing argument values, i.e.

  first call  = Meta-1 insert-last-word
  second call = Meta-2 insert-last-word
  third call  = Meta-3 insert-last-word

...

Bye

Dominik ^_^  ^_^

-- 
Dominik Vogt, email: d.vogt@lifebits.de
LifeBits Aktiengesellschaft, Albrechtstr. 9, D-72072 Tuebingen
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