From: Haakon Riiser <haakon.riiser@fys.uio.no>
To: zsh-users@sunsite.dk
Subject: Readline-like ^W behavior
Date: Thu, 3 Jul 2003 14:50:04 +0200 [thread overview]
Message-ID: <20030703125004.GA1792@s.chello.no> (raw)
Is it possible to make ^W delete the word to the left of the cursor
with the same word-boundary rules as in readline/bash? Here's what
I'm looking for:
bash$ ls foo-bar | wc^W
=> bash$ ls foo-bar | ^W
=> bash$ ls foo-bar ^W
=> bash$ ls ^W
=> bash$
I currently have ^W bound to "backward-kill-word" in zsh 4.1.1,
and it behaves like this:
zsh% ls foo-bar | wc^W
=> zsh% ls foo-bar | ^W
=> zsh% ls ^W
=> zsh%
As you can see from the above, the problem is that the second ^W
delets both the "|" and the word before it. This is apparently how
the "werase" character works in canonical mode (Linux 2.4.x), though
I can't imagine why -- does it consider "|" a whitespace character?
I've also tried "vi-backward-kill-word", but it's too weak:
zsh% ls foo-bar | wc^W
=> zsh% ls foo-bar | ^W
=> zsh% ls foo-bar ^W
=> zsh% ls foo-^W
=> zsh% ls foo^W
=> zsh% ls ^W
=> zsh%
Have I overlooked a function that corresponds to the readline
"unix-word-rubout" function?
--
Haakon
next reply other threads:[~2003-07-03 12:50 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2003-07-03 12:50 Haakon Riiser [this message]
2003-07-03 13:21 ` Peter Stephenson
2003-07-03 14:40 ` Haakon Riiser
2003-07-03 14:48 ` Peter Stephenson
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