RE: IFS, set, and positional parameters not doing what I expect

RE: IFS, set, and positional parameters not doing what I expect

[jason]

> -------- Original Message --------
> Subject: Re: IFS, set, and positional parameters not doing what I
> 
> Works For Me (tm):
> 
> schaefer<501> setopt shwordsplit 
> schaefer<502> f="a:b:c"
> schaefer<503> OFS=$IFS; IFS=: ; set -- $f ; IFS=$OFS
> schaefer<504> echo $1
> a

I must be on drugs.  I swear I tried that 3 different ways and
it didn't work.

Naturally, it works fine now.  Thanks!

--
Jason

Re: IFS, set, and positional parameters not doing what I expect

[Bart Schaefer]

On Mar 28,  3:04pm, jason@jnj.org wrote:
}
} f="a:b:c"
} OFS=$IFS; IFS=: ; set -- $f ; IFS=$OFS
} 
} which sets $1=a, $2=b, $3=c.

This requires either

	set -- ${=f}

Or that you have `setopt sh_word_split'.

} In zsh, this sets $1=a:b:c.  I've tried mucking around with
} the word splitting options to no avail.

Works For Me (tm):

schaefer<501> setopt shwordsplit 
schaefer<502> f="a:b:c"
schaefer<503> OFS=$IFS; IFS=: ; set -- $f ; IFS=$OFS
schaefer<504> echo $1
a
schaefer<505> echo $2
b
schaefer<506> echo $3
c

IFS, set, and positional parameters not doing what I expect

[jason]

Howdy

In bash and ksh, I do this a lot:

f="a:b:c"
OFS=$IFS; IFS=: ; set -- $f ; IFS=$OFS

which sets $1=a, $2=b, $3=c.

In zsh, this sets $1=a:b:c.  I've tried mucking around with
the word splitting options to no avail.

What am I missing?

--
Jason