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Date: Sat, 9 Jul 2005 17:17:36 +0200
From: DervishD <zsh@dervishd.net>
To: Meino Christian Cramer <Meino.Cramer@gmx.de>
Cc: zsh-users@sunsite.dk
Subject: Re: Asking ZSH: How are you ?
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    Hi Meino :)

 * Meino Christian Cramer <Meino.Cramer@gmx.de> dixit:
>        When listing options (*** by `setopt', `unsetopt', `set -o' or
>        `set +o'***), those turned on by default appear in the list
>        prefixed with `no'.  Hence (unless KSH_OPTION_PRINT is set),
>        `setopt' shows all options whose settings are changed from the
>        default.
> 
>   but giving "setopt +o" or "setopt -o"
>   always gives me (even for setopt +o!):
> 
> 	   setopt: string expected after -o

    Of course it does, it's correct ;) You're mixing 'set +o/-o' with
'setopt' and 'unsetopt'. If you want to list all options use
'setopt', without arguments, or 'set -o'. If you want to show ALL
options, no matter if they have their default value or not, use this
little snippet (for example):

    for option in ${(ko)options}; print ${(r:21:}option $options[$option]

    This will give you the list of all option names followed by its
value. I find this easier to understand that the default of prefixing
with 'no' and the like.

    Raúl Núñez de Arenas Coronado

-- 
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