From: DervishD <zsh@dervishd.net>
To: Zsh Users <zsh-users@sunsite.dk>
Subject: Re: Printing square brackets and backslashes
Date: Mon, 24 Oct 2005 02:04:08 +0200 [thread overview]
Message-ID: <20051024000408.GA1124@DervishD> (raw)
In-Reply-To: <20051023214319.GA633@DervishD>
Hi all :)
Just a note:
* DervishD <zsh@dervishd.net> dixit:
> Hi all :)
>
> $ print \[\\\]
> []
> $ /bin/echo -e \[\\\]
> [\]
> $ print -r \[\\\]
> [\]
> $ print \\
> \
I can understand the first case, but I don't understand the last
one: in the first case, what I misunderstood is that the shell quotes
the chars, producing "[\]" and "print" prints them, interpreting some
escape directives: "[]". But in the last case, nothing should then be
printed, because zsh quotes the backslash and "print" gets a single
backslash, that is, an empty escape directive that shouldn't print
anything :? Is "print" assuming that a single backslash is not an
empty escape directive? Is a single, isolated backslash a synonim for
"\\"?
Raúl Núñez de Arenas Coronado
--
Linux Registered User 88736 | http://www.dervishd.net
http://www.pleyades.net & http://www.gotesdelluna.net
It's my PC and I'll cry if I want to...
next prev parent reply other threads:[~2005-10-24 0:03 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2005-10-23 21:43 DervishD
2005-10-24 0:04 ` DervishD [this message]
2005-10-24 0:30 ` Chris Johnson
2005-10-24 8:16 ` DervishD
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