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Date: Mon, 24 Oct 2005 02:04:08 +0200
From: DervishD <zsh@dervishd.net>
To: Zsh Users <zsh-users@sunsite.dk>
Subject: Re: Printing square brackets and backslashes
Message-ID: <20051024000408.GA1124@DervishD>
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	version=3.0.4

    Hi all :)

    Just a note:

 * DervishD <zsh@dervishd.net> dixit:
>     Hi all :)
> 
>     $ print \[\\\]
>     []
>     $ /bin/echo -e \[\\\]
>     [\]
>     $ print -r \[\\\]
>     [\]
>     $ print \\
>     \

    I can understand the first case, but I don't understand the last
one: in the first case, what I misunderstood is that the shell quotes
the chars, producing "[\]" and "print" prints them, interpreting some
escape directives: "[]". But in the last case, nothing should then be
printed, because zsh quotes the backslash and "print" gets a single
backslash, that is, an empty escape directive that shouldn't print
anything :? Is "print" assuming that a single backslash is not an
empty escape directive? Is a single, isolated backslash a synonim for
"\\"?

    Raúl Núñez de Arenas Coronado

-- 
Linux Registered User 88736 | http://www.dervishd.net
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