From: DervishD <zsh@dervishd.net>
To: Zsh Users <zsh-users@sunsite.dk>
Subject: Per line ${..//..}
Date: Wed, 26 Oct 2005 11:40:47 +0200 [thread overview]
Message-ID: <20051026094047.GA658@DervishD> (raw)
Hi all :)
I have a parameter containing a bunch of lines, and I have to get
rid of comments (that is "$line" == (#s)[" $'\t'"]#\#*(#e)) and empty
lines (that is "$line" == (#s)[" $'\t'"]#(#e)). I've tried using the
${..//..} syntax for doing substitutions in parameters, but with no
success because I don't know how to properly mark the beginning and
end of a line.
So I'm using this:
for line in ${(f)olddata}
do
[[ "$line" == (#s)[" $'\t'"]#(\#*)#(#e) ]] && continue
newdata+=($line)
done
I'm pretty sure that this is not the best way of "cleaning" the
contents, but I can't think of anything better :( Any idea? Can the
${..//..} construct be used?
Thanks in advance :)
Raúl Núñez de Arenas Coronado
--
Linux Registered User 88736 | http://www.dervishd.net
http://www.pleyades.net & http://www.gotesdelluna.net
It's my PC and I'll cry if I want to...
next reply other threads:[~2005-10-26 9:40 UTC|newest]
Thread overview: 5+ messages / expand[flat|nested] mbox.gz Atom feed top
2005-10-26 9:40 DervishD [this message]
2005-10-26 9:47 ` Peter Stephenson
2005-10-26 10:15 ` DervishD
2005-10-26 10:27 ` Peter Stephenson
2005-10-26 11:26 ` DervishD
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