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Date: Wed, 26 Oct 2005 11:40:47 +0200
From: DervishD <zsh@dervishd.net>
To: Zsh Users <zsh-users@sunsite.dk>
Subject: Per line ${..//..}
Message-ID: <20051026094047.GA658@DervishD>
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	version=3.0.4

    Hi all :)

    I have a parameter containing a bunch of lines, and I have to get
rid of comments (that is "$line" == (#s)[" $'\t'"]#\#*(#e)) and empty
lines (that is "$line" == (#s)[" $'\t'"]#(#e)). I've tried using the
${..//..} syntax for doing substitutions in parameters, but with no
success because I don't know how to properly mark the beginning and
end of a line.

    So I'm using this:

for line in ${(f)olddata}
do
    [[ "$line" == (#s)[" $'\t'"]#(\#*)#(#e) ]] && continue
    newdata+=($line)
done

    I'm pretty sure that this is not the best way of "cleaning" the
contents, but I can't think of anything better :( Any idea? Can the
${..//..} construct be used?

    Thanks in advance :)

    Raúl Núñez de Arenas Coronado

-- 
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