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From: Frank Terbeck <ft@bewatermyfriend.de>
To: zsh-users@sunsite.dk
Subject: Re: I want to list the NEXT line after a string appears in a list of files
Date: Fri, 01 Sep 2006 17:15:17 +0200	[thread overview]
Message-ID: <20060901151517.GC18634@fsst.voodoo.lan> (raw)
In-Reply-To: <Xns9831A29573C98zzappergmailcom@80.91.229.5>

zzapper <david@tvis.co.uk>:
> I want to list the NEXT line after a string appears in a list of files
> 
> eg 
> > egrep "Anecdote" m??.txt (But display next line)
> 
> I guess Sed/Awk would do this, I would probably use Perl.
> 
> Suggestions pls

[snip]
zsh% cat test0.txt                                           
These             
are
lines,
I
do
not
care
about.
but
please
display this line.
zsh% cat test1.txt                                           
and please, oh please:
display this line, too.
not
this
one
zsh% function my_grep () {                                   
  local integer found=0
  while read line ; do
    (( found == 1 )) && print ${line} && return
    (( found == 0 )) && [[ ${line} = *${1}* ]] && found=1
  done < ${2}
}
zsh% for file in test*.txt ; do my_grep 'please' $file ; done
display this line.                                           
display this line, too.
[snap]

Regards, Frank


  parent reply	other threads:[~2006-09-02  7:16 UTC|newest]

Thread overview: 9+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2006-09-01 14:59 zzapper
2006-09-01 15:15 ` John Eikenberry
2006-09-02 13:59   ` zzapper
2006-09-01 15:15 ` Frank Terbeck [this message]
2006-09-02 18:41   ` zzapper
2006-09-01 15:27 ` Roman Cheplyaka
2006-09-01 15:36   ` zzapper
2006-09-01 15:28 ` Chris Johnson
2006-09-01 16:52 ` Marc Chantreux

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