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From: Marc Chantreux <marc.chantreux@ulpmm.u-strasbg.fr>
To: zsh-users@sunsite.dk
Subject: Re: I want to list the NEXT line after a string appears in a list of files
Date: Fri, 1 Sep 2006 18:52:36 +0200	[thread overview]
Message-ID: <20060901165235.GA2122@ulpmm.u-strasbg.fr> (raw)
In-Reply-To: <Xns9831A29573C98zzappergmailcom@80.91.229.5>

le 01/09/2006,
zzapper nous écrivait :
> Hi
> I want to list the NEXT line after a string appears in a list of files

choose your destiny : 

- little files : zsh 
- medium       : sed/awk (1)
- big          : perl

(1) every one but the GNU one which is damn slow ! 

echo '
find a 
find a 
find a 
find a 
pattern
x
and print it
' > file

print sed:
sed -n '/pattern/ { # if pattern found
  n  # read next line
  p  # print the current line
}' < file

print wich can be written as:
sed -n '/pattern/{n;p}' < file

print perl:
perl -lne 'print $_=<> if /pattern/' file

print awk:
awk '/pattern/ { getline ; print }' file


print zsh -----------------
print first occurence :

# 1. store the content of file, line by line
content=( ${(f)"$( < file)"} )

# find a line containing your pattern 
# > ${content[(i)*pattern*]}
# and print the next one
print ${content[${content[(i)*pattern*]} + 1]}

print all occurences :

while {read} {
    [[ $REPLY == *pattern* ]] &&
	read line &&
	print $line
} < file


regards

-- 
téléphone : 03.90.24.00.19
courriel  : marc.chantreux@ulpmm.u-strasbg.fr
---------------------------------------


      parent reply	other threads:[~2006-09-01 16:52 UTC|newest]

Thread overview: 9+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2006-09-01 14:59 zzapper
2006-09-01 15:15 ` John Eikenberry
2006-09-02 13:59   ` zzapper
2006-09-01 15:15 ` Frank Terbeck
2006-09-02 18:41   ` zzapper
2006-09-01 15:27 ` Roman Cheplyaka
2006-09-01 15:36   ` zzapper
2006-09-01 15:28 ` Chris Johnson
2006-09-01 16:52 ` Marc Chantreux [this message]

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