* get array of integers?
@ 2006-09-03 16:59 sam reckoner
2006-09-03 17:55 ` Bart Schaefer
2006-09-03 20:27 ` Roman Cheplyaka
0 siblings, 2 replies; 4+ messages in thread
From: sam reckoner @ 2006-09-03 16:59 UTC (permalink / raw)
To: zsh-users
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I have been doing
x=$(){1..10}
to get a range of integers. Is there a better way? Also, how can I get a
range that steps by 2 instead of by 1 as in
1 3 5 7 ...
Thanks!
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^ permalink raw reply [flat|nested] 4+ messages in thread
* Re: get array of integers?
2006-09-03 16:59 get array of integers? sam reckoner
@ 2006-09-03 17:55 ` Bart Schaefer
2006-09-03 20:27 ` Roman Cheplyaka
1 sibling, 0 replies; 4+ messages in thread
From: Bart Schaefer @ 2006-09-03 17:55 UTC (permalink / raw)
To: zsh-users
On Sep 3, 9:59am, sam reckoner wrote:
}
} I have been doing
}
} x=$(){1..10}
That's a typo? You mean
x=( {1..10} )
} Is there a better way?
Probably not, except maybe to skip generating the array at all and use a
"for (( x=1; x <= 10; ++x ))" loop. Depends on context, of course.
(Make sure "x" is not already defined as an array, or that loop will
not work properly. Best to explicitly declare "integer x".)
} Also, how can I get a range that steps by 2 instead of by 1 as in
}
} 1 3 5 7 ...
By being sneaky.
typeset -A x
x=( {1..10} )
Now ${(k)x} is an array of odd numbers, and ${(v)x} is an array of
even numbers. To get them in ascending order, use ${(nok)x}. Note
that you have to assign an even number of numbers, that is
x=( {1..9} )
will print an error message and not do the assignment.
Of course this trick doesn't work if you want an array by anything
other than twos. So a more general approach (if you really want to
avoid that "for" loop) would be
typeset -a x
# Count by 7s from 7 to 70
x=( '$(('{1..10}'*7))' )
x=( ${(e)x} )
# Count by 5s from 1 to 51
x=( '$(('{1..10}'*5+1))' )
x=( 1 ${(e)x} )
Of course you can also get really silly:
# Count by 3s from 3 to 30
setopt extendedglob
typeset -a x
x=( {1..10} )
x=( ${x//(#b)(*)/$(($match*3))} )
That's doing a lot of extra work behind the scenes, though, to match
the pattern, store the backreference, etc.
^ permalink raw reply [flat|nested] 4+ messages in thread
* Re: get array of integers?
2006-09-03 16:59 get array of integers? sam reckoner
2006-09-03 17:55 ` Bart Schaefer
@ 2006-09-03 20:27 ` Roman Cheplyaka
2006-09-03 21:34 ` Dan Nelson
1 sibling, 1 reply; 4+ messages in thread
From: Roman Cheplyaka @ 2006-09-03 20:27 UTC (permalink / raw)
To: zsh-users
On Sun, Sep 03, 2006 at 09:59:21AM -0700, sam reckoner wrote:
> I have been doing
>
> x=$(){1..10}
>
> to get a range of integers. Is there a better way? Also, how can I get a
> range that steps by 2 instead of by 1 as in
>
> 1 3 5 7 ...
Take a look at seq(1).
--
Roman I. Cheplyaka
^ permalink raw reply [flat|nested] 4+ messages in thread
* Re: get array of integers?
2006-09-03 20:27 ` Roman Cheplyaka
@ 2006-09-03 21:34 ` Dan Nelson
0 siblings, 0 replies; 4+ messages in thread
From: Dan Nelson @ 2006-09-03 21:34 UTC (permalink / raw)
To: Roman Cheplyaka; +Cc: zsh-users
In the last episode (Sep 03), Roman Cheplyaka said:
> On Sun, Sep 03, 2006 at 09:59:21AM -0700, sam reckoner wrote:
> > I have been doing
> >
> > x=$(){1..10}
> >
> > to get a range of integers. Is there a better way? Also, how can
> > I get a range that steps by 2 instead of by 1 as in
> >
> > 1 3 5 7 ...
>
> Take a look at seq(1).
or jot(1) , depending on what OS you are on.
--
Dan Nelson
dnelson@allantgroup.com
^ permalink raw reply [flat|nested] 4+ messages in thread
end of thread, other threads:[~2006-09-03 21:34 UTC | newest]
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2006-09-03 16:59 get array of integers? sam reckoner
2006-09-03 17:55 ` Bart Schaefer
2006-09-03 20:27 ` Roman Cheplyaka
2006-09-03 21:34 ` Dan Nelson
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