* Double Evaluation Question (not in FAQ)
@ 2006-09-04 6:18 Com MN PG P E B Consultant 3
2006-09-04 6:28 ` Stephane Chazelas
0 siblings, 1 reply; 2+ messages in thread
From: Com MN PG P E B Consultant 3 @ 2006-09-04 6:18 UTC (permalink / raw)
To: zsh-users Mailinglist
Assuming that variables are assigned in the following way:
x=abc
y=def
z='$x $y' # Note: Single Quotes!
How could I write an expression, which "evaluates" $z, in
that it would return "abc def"? The simple
eval "echo $z"
would not work here, because it would not
preserve the spaces.
eval "echo \"$z\""
would indeed do the job, but I consider this a very ugly
solution because of the nested quoting. Does anyone know
a more elegant alternative?
Ronald
--
Ronald Fischer (phone +49-89-63676431)
mailto:mn-pg-p-e-b-consultant-3.com@siemens.com
^ permalink raw reply [flat|nested] 2+ messages in thread
* Re: Double Evaluation Question (not in FAQ)
2006-09-04 6:18 Double Evaluation Question (not in FAQ) Com MN PG P E B Consultant 3
@ 2006-09-04 6:28 ` Stephane Chazelas
0 siblings, 0 replies; 2+ messages in thread
From: Stephane Chazelas @ 2006-09-04 6:28 UTC (permalink / raw)
To: zsh-users Mailinglist
On Mon, Sep 04, 2006 at 08:18:19AM +0200, Com MN PG P E B Consultant 3 wrote:
> Assuming that variables are assigned in the following way:
>
> x=abc
> y=def
> z='$x $y' # Note: Single Quotes!
>
> How could I write an expression, which "evaluates" $z, in
> that it would return "abc def"? The simple
>
> eval "echo $z"
>
> would not work here, because it would not
> preserve the spaces.
[...]
print -r -- ${(e)z}
--
Stéphane
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