From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 13963 invoked by alias); 10 Jul 2010 15:07:02 -0000 Mailing-List: contact zsh-users-help@zsh.org; run by ezmlm Precedence: bulk X-No-Archive: yes List-Id: Zsh Users List List-Post: List-Help: X-Seq: 15155 Received: (qmail 19386 invoked from network); 10 Jul 2010 15:06:58 -0000 X-Spam-Checker-Version: SpamAssassin 3.3.1 (2010-03-16) on f.primenet.com.au X-Spam-Level: X-Spam-Status: No, score=-1.9 required=5.0 tests=BAYES_00 autolearn=ham version=3.3.1 Received-SPF: none (ns1.primenet.com.au: domain at plenz.com does not designate permitted sender hosts) Date: Sat, 10 Jul 2010 16:57:28 +0200 From: Julius Plenz To: zsh-users@zsh.org Subject: Re: Assign to parameter in parameter -- opposite of ${(P)name}? Message-ID: <20100710145728.GK3043@plenz.com> Mail-Followup-To: zsh-users@zsh.org References: MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Disposition: inline In-Reply-To: X-Editor: vim 7.1 User-Agent: Mutt/1.5.18 (2008-05-17) Hi, Benjamin! * Benjamin R. Haskell [2010-07-10 01:35]: > but how do you *assign* to a parameter whose name is in a parameter? > name=foo > : ${${(P)name}::=something} > echo $foo > # should echo 'something' How about: zsh> name=foo zsh> typeset $name=something zsh> echo $foo something Julius