Re: Why the l parameter flag in this case not work?

[lilydjwg <lilydjwg@gmail.com>]

On Tue, Mar 20, 2012 at 09:57:08AM +0100, Damien Thébault wrote:
> On Tue, Mar 20, 2012 at 09:32, lilydjwg <lilydjwg@gmail.com> wrote:
> > I tried to print a line of `-' but not work:
> >
> > print ${(l.80..-.)}
> >
> > An empty line is printed. However, printing a line of `=' or other
> > strings do work:
> >
> > print ${(l.80..+.)}
> >
> > I tried to quote `-', but only 40 `-'s are printed:
> >
> > print ${(l.80..\-.)}
> >
> 
> The "print" command is intepreting the expanded expression as an
> argument, you can use "echo" or use "--" to tell the "print" command
> that the end of arguments has been reached:
> 
> echo ${(l.80..-.)}
> print -- ${(l.80..-.)}

Thanks!

-- 
Best regards,
lilydjwg