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Date: Tue, 20 Mar 2012 21:41:46 +0800
From: lilydjwg <lilydjwg@gmail.com>
To: zsh-users@zsh.org
Subject: Re: Why the l parameter flag in this case not work?
Message-ID: <20120320134146.GA1825@lilyforest>
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References: <20120320083214.GA3818@lilyforest>
 <CAEcrOvCsRGsfvCO_n6HfkjG=_REbGuu4nCTbb+zZK7w+_2o+xw@mail.gmail.com>
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User-Agent: Mutt/1.5.21 (2010-09-15)

On Tue, Mar 20, 2012 at 09:57:08AM +0100, Damien Thébault wrote:
> On Tue, Mar 20, 2012 at 09:32, lilydjwg <lilydjwg@gmail.com> wrote:
> > I tried to print a line of `-' but not work:
> >
> > print ${(l.80..-.)}
> >
> > An empty line is printed. However, printing a line of `=' or other
> > strings do work:
> >
> > print ${(l.80..+.)}
> >
> > I tried to quote `-', but only 40 `-'s are printed:
> >
> > print ${(l.80..\-.)}
> >
> 
> The "print" command is intepreting the expanded expression as an
> argument, you can use "echo" or use "--" to tell the "print" command
> that the end of arguments has been reached:
> 
> echo ${(l.80..-.)}
> print -- ${(l.80..-.)}

Thanks!

-- 
Best regards,
lilydjwg