* Why the l parameter flag in this case not work?
@ 2012-03-20 8:32 lilydjwg
2012-03-20 8:57 ` Damien Thébault
0 siblings, 1 reply; 3+ messages in thread
From: lilydjwg @ 2012-03-20 8:32 UTC (permalink / raw)
To: zsh-users
I tried to print a line of `-' but not work:
print ${(l.80..-.)}
An empty line is printed. However, printing a line of `=' or other
strings do work:
print ${(l.80..+.)}
I tried to quote `-', but only 40 `-'s are printed:
print ${(l.80..\-.)}
My zsh is version 4.3.17.
--
Best regards,
lilydjwg
^ permalink raw reply [flat|nested] 3+ messages in thread* Re: Why the l parameter flag in this case not work?
2012-03-20 8:32 Why the l parameter flag in this case not work? lilydjwg
@ 2012-03-20 8:57 ` Damien Thébault
2012-03-20 13:41 ` lilydjwg
0 siblings, 1 reply; 3+ messages in thread
From: Damien Thébault @ 2012-03-20 8:57 UTC (permalink / raw)
To: zsh-users
On Tue, Mar 20, 2012 at 09:32, lilydjwg <lilydjwg@gmail.com> wrote:
> I tried to print a line of `-' but not work:
>
> print ${(l.80..-.)}
>
> An empty line is printed. However, printing a line of `=' or other
> strings do work:
>
> print ${(l.80..+.)}
>
> I tried to quote `-', but only 40 `-'s are printed:
>
> print ${(l.80..\-.)}
>
The "print" command is intepreting the expanded expression as an
argument, you can use "echo" or use "--" to tell the "print" command
that the end of arguments has been reached:
echo ${(l.80..-.)}
print -- ${(l.80..-.)}
Regards,
--
Damien Thebault
^ permalink raw reply [flat|nested] 3+ messages in thread* Re: Why the l parameter flag in this case not work?
2012-03-20 8:57 ` Damien Thébault
@ 2012-03-20 13:41 ` lilydjwg
0 siblings, 0 replies; 3+ messages in thread
From: lilydjwg @ 2012-03-20 13:41 UTC (permalink / raw)
To: zsh-users
On Tue, Mar 20, 2012 at 09:57:08AM +0100, Damien Thébault wrote:
> On Tue, Mar 20, 2012 at 09:32, lilydjwg <lilydjwg@gmail.com> wrote:
> > I tried to print a line of `-' but not work:
> >
> > print ${(l.80..-.)}
> >
> > An empty line is printed. However, printing a line of `=' or other
> > strings do work:
> >
> > print ${(l.80..+.)}
> >
> > I tried to quote `-', but only 40 `-'s are printed:
> >
> > print ${(l.80..\-.)}
> >
>
> The "print" command is intepreting the expanded expression as an
> argument, you can use "echo" or use "--" to tell the "print" command
> that the end of arguments has been reached:
>
> echo ${(l.80..-.)}
> print -- ${(l.80..-.)}
Thanks!
--
Best regards,
lilydjwg
^ permalink raw reply [flat|nested] 3+ messages in thread
end of thread, other threads:[~2012-03-20 13:42 UTC | newest]
Thread overview: 3+ messages (download: mbox.gz / follow: Atom feed)
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2012-03-20 8:32 Why the l parameter flag in this case not work? lilydjwg
2012-03-20 8:57 ` Damien Thébault
2012-03-20 13:41 ` lilydjwg
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