From: Han Pingtian <hanpt@linux.vnet.ibm.com>
To: zsh-user <zsh-users@zsh.org>
Subject: z flag in parameter expansion doesn't use $IFS ?
Date: Fri, 19 Oct 2012 06:18:26 +0800 [thread overview]
Message-ID: <20121018221826.GA6056@localhost.localdomain> (raw)
Hello,
It looks like the z flag of parameter expansion doesn't care what the
value of IFS is:
% zsh -c 'var="foo ''bar baz''";print -l ${(z)var}'
foo
'bar baz'
% zsh -c 'IFS=:;var="foo:''bar:baz''";print -l ${=var}'
foo
'bar
baz'
% zsh -c 'IFS=:;var="foo:''bar:baz''";print -l ${(z)var}'
foo:'bar:baz'
%
I believe z flag should regard IFS and split expansion results just like
the shell parsing. Or I'm missing something here? Please help.
Thanks in advance.
next reply other threads:[~2012-10-18 22:29 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2012-10-18 22:18 Han Pingtian [this message]
2012-10-19 8:26 ` Peter Stephenson
2012-10-19 8:53 ` Han Pingtian
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