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Date: Fri, 19 Oct 2012 06:18:26 +0800
From: Han Pingtian <hanpt@linux.vnet.ibm.com>
To: zsh-user <zsh-users@zsh.org>
Subject: z flag in parameter expansion doesn't use $IFS ?
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Hello, 

It looks like the z flag of parameter expansion doesn't care what the
value of IFS is:

% zsh -c 'var="foo ''bar baz''";print -l ${(z)var}'
foo
'bar baz'
% zsh -c 'IFS=:;var="foo:''bar:baz''";print -l ${=var}'
foo
'bar
baz'
% zsh -c 'IFS=:;var="foo:''bar:baz''";print -l ${(z)var}'
foo:'bar:baz'
%

I believe z flag should regard IFS and split expansion results just like
the shell parsing. Or I'm missing something here? Please help.

Thanks in advance.