* flag z won't cause forced joining? @ 2012-10-19 8:03 Han Pingtian 2012-10-19 15:38 ` Bart Schaefer 0 siblings, 1 reply; 3+ messages in thread From: Han Pingtian @ 2012-10-19 8:03 UTC (permalink / raw) To: zsh-user Hi, I just found that it looks like the z flag won't cause "forced joining" which stated in rules 10, like this: % typeset -a arr;arr[1]=foo;arr[2]=\'bar;arr[3]=baz\';print -l ${(z)arr} foo 'bar baz' % typeset -a arr;arr[1]=foo;arr[2]=\'bar;arr[3]=baz\';print -l ${(z)"${arr}"} foo 'bar baz' % Not sure is it a problem. Please help. Thanks in advance. ^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: flag z won't cause forced joining? 2012-10-19 8:03 flag z won't cause forced joining? Han Pingtian @ 2012-10-19 15:38 ` Bart Schaefer 2012-10-19 23:34 ` Han Pingtian 0 siblings, 1 reply; 3+ messages in thread From: Bart Schaefer @ 2012-10-19 15:38 UTC (permalink / raw) To: zsh-user On Oct 19, 4:03pm, Han Pingtian wrote: } } I just found that it looks like the z flag won't cause "forced joining" } which stated in rules 10 Yes, this is a case of the documentation being wrong; it was recently corrected. Rule 10 now says: 10. _Forced joining_ If the `(j)' flag is present, or no `(j)' flag is present but the string is to be split as given by rule 11., and joining did not take place at step 5., any words in the value are joined together using the given string or the first character of $IFS if none. Note that the `(F)' flag implicitly supplies a string for joining in this manner. 11. _Simple word splitting_ If one of the `(s)' or `(f)' flags are present, or the `=' specifier was present (e.g. ${=VAR}), the word is split on occurrences of the specified string, or (for = with neither of the two flags present) any of the characters in $IFS. If no `(s)', `(f)' or `=' was given, but the word is not quoted and the option SH_WORD_SPLIT is set, the word is split on occurrences of any of the characters in $IFS. Note this step, too, takes place at all levels of a nested substitution. Note that the reference to rule 17 [the (z) flag] has been removed from rule 10 (and rule 11 is new). ^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: flag z won't cause forced joining? 2012-10-19 15:38 ` Bart Schaefer @ 2012-10-19 23:34 ` Han Pingtian 0 siblings, 0 replies; 3+ messages in thread From: Han Pingtian @ 2012-10-19 23:34 UTC (permalink / raw) To: zsh-users On Fri, Oct 19, 2012 at 08:38:18AM -0700, Bart Schaefer wrote: > On Oct 19, 4:03pm, Han Pingtian wrote: > } > } I just found that it looks like the z flag won't cause "forced joining" > } which stated in rules 10 > > Yes, this is a case of the documentation being wrong; it was recently > corrected. Rule 10 now says: > > 10. _Forced joining_ > If the `(j)' flag is present, or no `(j)' flag is present but the > string is to be split as given by rule 11., and joining did not > take place at step 5., any words in the value are joined together > using the given string or the first character of $IFS if none. > Note that the `(F)' flag implicitly supplies a string for joining > in this manner. > > 11. _Simple word splitting_ > If one of the `(s)' or `(f)' flags are present, or the `=' > specifier was present (e.g. ${=VAR}), the word is split on > occurrences of the specified string, or (for = with neither of the > two flags present) any of the characters in $IFS. > > If no `(s)', `(f)' or `=' was given, but the word is not quoted > and the option SH_WORD_SPLIT is set, the word is split on > occurrences of any of the characters in $IFS. Note this step, too, > takes place at all levels of a nested substitution. > > Note that the reference to rule 17 [the (z) flag] has been removed from > rule 10 (and rule 11 is new). Thanks a lot. ^ permalink raw reply [flat|nested] 3+ messages in thread
end of thread, other threads:[~2012-10-19 23:45 UTC | newest] Thread overview: 3+ messages (download: mbox.gz / follow: Atom feed) -- links below jump to the message on this page -- 2012-10-19 8:03 flag z won't cause forced joining? Han Pingtian 2012-10-19 15:38 ` Bart Schaefer 2012-10-19 23:34 ` Han Pingtian
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