From: Phil Pennock <zsh-workers+phil.pennock@spodhuis.org>
To: TJ Luoma <luomat@gmail.com>
Cc: Zsh-Users List <zsh-users@zsh.org>
Subject: Re: why isn't IFS=$'\n' doing what I expect it to do here?
Date: Sun, 24 Mar 2013 00:46:41 -0400 [thread overview]
Message-ID: <20130324044640.GA73632@redoubt.spodhuis.org> (raw)
In-Reply-To: <CADjGqHtU3bNfYMdUCNGBpJsB-6gsq2boT6X3Qevwr8VF_U5PHg@mail.gmail.com>
On 2013-03-23 at 23:27 -0400, TJ Luoma wrote:
> > Similarly, you can use:
> > APPS=(${=${:-'
> > for the first line, to actually split on $IFS, in which case changing
> > IFS does affect parsing here.
> >
> > -Phil
> >
>
> If I do that then I can no longer use "$f[5]" to refer to the 5th _line_ …
> I end up getting a single character instead of a line.
Then something is strange in your environment.
The (f) forces splitting on lines, resulting in an array, and is
assigned inside APPS=( ... ).
Similarly for the = (which uses $IFS to split).
I've just confirmed with "zsh -f" that this works just fine with default
options. I suspect that you missed the outer ${(f) ... } wrapper.
-Phil
next prev parent reply other threads:[~2013-03-24 4:46 UTC|newest]
Thread overview: 5+ messages / expand[flat|nested] mbox.gz Atom feed top
2013-03-24 2:01 TJ Luoma
2013-03-24 3:09 ` Phil Pennock
2013-03-24 3:27 ` TJ Luoma
2013-03-24 4:46 ` Phil Pennock [this message]
2013-03-24 3:47 ` Bart Schaefer
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