From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 14751 invoked by alias); 20 Sep 2013 11:21:40 -0000 Mailing-List: contact zsh-users-help@zsh.org; run by ezmlm Precedence: bulk X-No-Archive: yes List-Id: Zsh Users List List-Post: List-Help: X-Seq: 17983 Received: (qmail 22938 invoked from network); 20 Sep 2013 11:21:33 -0000 X-Spam-Checker-Version: SpamAssassin 3.3.2 (2011-06-06) on f.primenet.com.au X-Spam-Level: X-Spam-Status: No, score=-6.9 required=5.0 tests=BAYES_00,RCVD_IN_DNSWL_HI autolearn=ham version=3.3.2 Received-SPF: none (ns1.primenet.com.au: domain at linux.vnet.ibm.com does not designate permitted sender hosts) Date: Fri, 20 Sep 2013 19:11:10 +0800 From: Han Pingtian To: zsh-users@zsh.org Subject: question about glob qualifier format (#qx) Message-ID: <20130920111110.GA4501@localhost.localdomain> MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Disposition: inline User-Agent: Mutt/1.5.21 (2010-09-15) X-TM-AS-MML: No X-Content-Scanned: Fidelis XPS MAILER x-cbid: 13092011-0320-0000-0000-00000112312A Hello, I'm confused about the usage of glob qualifier format "(#qx)". The man page says: ...... Also, as the syntax is unambiguous, the expression will be treated as glob qualifiers just as long any parentheses contained within it are balanced; appearance of `|', `(' or `~' does not negate the effect. But looks like if I put them in parentheses, it will not take effect any more: $ ls 1.c 2.h a b slink $ echo *((#q/)) 1.c 2.h a b slink So I'd like to know how to comprehend the manpage here? Thanks in advance!