From: Dominik Vogt <vogt@linux.vnet.ibm.com>
To: Zsh Users <zsh-users@zsh.org>
Subject: Re: copying an array
Date: Fri, 8 Aug 2014 06:12:01 +0100 [thread overview]
Message-ID: <20140808051201.GA4539@linux.vnet.ibm.com> (raw)
In-Reply-To: <140805085527.ZM28041@torch.brasslantern.com>
On Tue, Aug 05, 2014 at 08:55:27AM -0700, Bart Schaefer wrote:
> On Aug 5, 6:44am, Dominik Vogt wrote:
> >
> > typeset -g -a G
> > G=("a b c" d e)
> > copy_array () {
> > typeset -g -a "$1"
> > # how can this be done?
> > $1="($G[@])"
> > }
>
> You probably don't need the function at all if this is the only thing it
> is doing:
>
> set -A "$1" "$G[@]"
Ah, I did not have "set" on the radar. Thanks!
> The only reason for the "typeset -g" would be if there is a local array
> in scope whose name is the same as the value of $1. Otherwise "set -A"
> will create the global array for you.
Is there a specific reason why typeset cannot initialize arrays?
Ciao
Dominik ^_^ ^_^
--
Dominik Vogt
IBM Germany
next prev parent reply other threads:[~2014-08-08 5:22 UTC|newest]
Thread overview: 5+ messages / expand[flat|nested] mbox.gz Atom feed top
2014-08-05 5:44 Dominik Vogt
2014-08-05 15:41 ` Yuya Amemiya
2014-08-05 15:55 ` Bart Schaefer
2014-08-08 5:12 ` Dominik Vogt [this message]
2014-08-08 6:07 ` Bart Schaefer
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