From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 5672 invoked by alias); 12 Jan 2015 06:10:54 -0000 Mailing-List: contact zsh-users-help@zsh.org; run by ezmlm Precedence: bulk X-No-Archive: yes List-Id: Zsh Users List List-Post: List-Help: X-Seq: 19729 Received: (qmail 856 invoked from network); 12 Jan 2015 06:10:51 -0000 X-Spam-Checker-Version: SpamAssassin 3.3.2 (2011-06-06) on f.primenet.com.au X-Spam-Level: X-Spam-Status: No, score=-1.9 required=5.0 tests=BAYES_00,FREEMAIL_FROM, RCVD_IN_DNSWL_NONE autolearn=ham version=3.3.2 Date: Mon, 12 Jan 2015 07:10:32 +0100 From: Meino.Cramer@gmx.de To: zsh-users@zsh.org Subject: Sort directory tree contents by time completly ? Message-ID: <20150112061032.GA12419@solfire> MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Disposition: inline User-Agent: mutt-ng/devel-r804 (Linux) X-Provags-ID: V03:K0:MzmXq14pj0Ugp1LnN/yk8ZgLMgl6nNdKdjaqShplXhBWVdNAaGN 46aSspdeILxCiSoJK1BCikX9/xkj8bCE73U4tBcrBJ6JSybZO5CBHP0Xea2sVzsoWDIMjQF 5tojG5bx3XUtnWysQ8BVWYGQ5odd1o2xniuf5QVn1ON1SDvpMC7AghROc6Oi1iBCUNFunYu WB/Jr2t4e+LolstF7sQYA== X-UI-Out-Filterresults: notjunk:1; Hi, Suppose there is a directory tree with very old, midaged and very ypung file in. There are also empty directories and symlinks. Is it possible with zsh to get a directory listing of *all* files in kind of the output of "ls -l", where all files are in one long list, which is sorted by the timestamp of those files -- one file per line and each file with a complete path (not necessary as absolute path but the directory should not be listed in the header. I dont want heades.??? Thank you very much for any help in advance! Best regards, mcc