From: Eric Pruitt <eric.pruitt@gmail.com>
To: zsh-users@zsh.org
Subject: Re: Running "unset path" breaks PATH despite emulation being enabled
Date: Sat, 9 Sep 2017 14:38:06 -0700 [thread overview]
Message-ID: <20170909213806.52qezvyk766loeg3@sinister.lan.codevat.com> (raw)
In-Reply-To: <CAHYJk3RD6p7PwRaZSUbJSAE0Bi6_2+NKLC3MV+32Lh+PmzsAdA@mail.gmail.com>
I'm moving this discussion from zsh-workers to zsh-users since it's been
established that the behavior I observed isn't necessarily a bug.
On Fri, Sep 08, 2017 at 01:30:05PM +0200, Mikael Magnusson wrote:
> This works fine if you start zsh as sh though, ie either make a
> symlink ln -s =zsh sh; ./sh or do ARGV0=sh zsh
> It can't really work in the 'emulate sh' case since the parameter
> $path is then already created and it would be quite controversial for
> emulate to remove parameters from the shell environment.
What I ended up doing is adding this to the top of my script:
test "${ZSH_NAME:-sh}" = "sh" || exec -a sh zsh "$0" "$@"
I would like to replace "zsh" with the absolute path of the Z shell
interpreter in case the "zsh" being executed is not the first one listed
in a $PATH folder. After reading through some documentation and
reviewing the output of "set", I don't see a way to do this. For
comparison, Bash sets $BASH to the interpreter's path:
~$ echo $BASH
/home/ericpruitt/.local/bin/bash
Is there a similar value in Z shell or a built-in I can use?
Thanks,
Eric
next parent reply other threads:[~2017-09-09 21:38 UTC|newest]
Thread overview: 7+ messages / expand[flat|nested] mbox.gz Atom feed top
[not found] <20170908082917.v5j4vczoq75vs5lk@sinister.lan.codevat.com>
[not found] ` <CAHYJk3RD6p7PwRaZSUbJSAE0Bi6_2+NKLC3MV+32Lh+PmzsAdA@mail.gmail.com>
2017-09-09 21:38 ` Eric Pruitt [this message]
2017-09-09 22:25 ` Bart Schaefer
2017-09-09 22:38 ` Eric Pruitt
2017-09-10 9:42 ` Daniel Shahaf
2017-09-10 23:50 ` Bart Schaefer
2017-09-11 4:39 ` Eric Pruitt
2017-09-10 18:51 ` Chet Ramey
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