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Date: Wed, 3 Oct 2018 23:06:14 +0200
From: Marc Chantreux <eiro@phear.org>
To: Bart Schaefer <schaefer@brasslantern.com>
Cc: Zsh Users <zsh-users@zsh.org>
Subject: Re: dangerous behavior of while in zsh 5.6 ?
Message-ID: <20181003210614.GA32575@prometheus.u-strasbg.fr>
References: <20181003143800.GA9162@prometheus.u-strasbg.fr>
 <CAH+w=7ZuFKDMBvL7XdSqYXcXy5hrc_zQPK0KsLrTZ1Szrfu6Ow@mail.gmail.com>
 <20181003162552.GA14697@prometheus.u-strasbg.fr>
 <CAH+w=7adyJUKgfCQz6yzEMUDMyqEi-B+akhi0Py4R37C-y82YQ@mail.gmail.com>
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User-Agent: Mutt/1.10.1 (2018-07-13)

hello,

    repeat 2 print $[i++]
    while ((i--))
        print $i

> >     {   repeat 2 print $[i++]
> >         while (( i-- )) print $i
> >     } |sed 10 | xargs

> This shows a critical missing bit of detail from your original
> message:  The while loop is inside a { } expression.

the way i wrote it was only to demonstrate but this is another example:

    # grep -n . /tmp/a.zsh
    1:repeat 2 print $[i++]
    2:while ((i--))
    3:    print $i
    # zsh /tmp/a.zsh | sed 10q
    0
    1
    1
    0
    -1
    -2
    -3
    -4
    -5
    -6

regards
marc