From: Ray Andrews <rayandrews@eastlink.ca>
To: zsh-users@zsh.org
Subject: Re: forcing float arithmetic.
Date: Wed, 24 Mar 2021 18:12:29 -0700 [thread overview]
Message-ID: <22260ea8-adec-6e16-9250-c2c2ab31fcba@eastlink.ca> (raw)
In-Reply-To: <CAH+w=7bOsdz17cfXTbNbwYXTJW_M9r67BnqVbNqkATZcU31=eQ@mail.gmail.com>
On 2021-03-24 2:59 p.m., Bart Schaefer wrote:
> On Wed, Mar 24, 2021 at 2:54 PM Roman Perepelitsa
> <roman.perepelitsa@gmail.com> wrote:
>> The behavior of zsh in this regard is consistent with C and all languages inspired by it (C++, Java, C# and many, many others). This is really working as intended.
> Proof:
>
> #include <stdio.h>
> void main() {
> int x = 3, y = 7;
> float z = (x/y);
> printf("%g\n", z);
> }
>
Long time since I did any floating point in C, so I'll take you guy's
word for it. Final shot would that since one can force the conversion
by, say, multiplying by 1.0, which is otherwise pointless, one could
imagine some option whereby the bother is simply not required.
(( aa = ((2 * nn) - 1) / (nn**2.0) ))
... in that case the denominator is not changed in any way, yet if flags
that the division should be passed as a float. Seems an awkward way of
getting the conversion. How is 2^2 different from 2^2.0 ? If 'aa' was
an integer then of course the result must be rounded, but it still seems
to me the float should receive the actual result. One of my little
whines, nothing of substance. Still one might dream of setopt AUTO_FLOAT.
next prev parent reply other threads:[~2021-03-25 1:13 UTC|newest]
Thread overview: 10+ messages / expand[flat|nested] mbox.gz Atom feed top
2021-03-24 17:19 Ray Andrews
2021-03-24 17:56 ` Bart Schaefer
2021-03-24 21:51 ` Ray Andrews
2021-03-24 21:54 ` Roman Perepelitsa
2021-03-24 21:59 ` Bart Schaefer
2021-03-25 1:12 ` Ray Andrews [this message]
2021-03-25 1:36 ` Daniel Shahaf
2021-03-25 1:45 ` Ray Andrews
2021-03-25 2:37 ` Bart Schaefer
2021-03-25 3:22 ` Ray Andrews
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