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Subject: Re: Mapping quoted parameter in function
From: Clint Hepner <clint.hepner@gmail.com>
In-Reply-To: <0a521f25-d548-d3b1-fb2e-7559f7995b7d@bernd-steinhauser.de>
Date: Thu, 10 Nov 2016 07:29:55 -0500
Cc: zsh-users@zsh.org
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Message-Id: <22F03E0F-5C12-41EC-BD57-72139A3534D7@gmail.com>
References: <0a521f25-d548-d3b1-fb2e-7559f7995b7d@bernd-steinhauser.de>
To: Bernd Steinhauser <linux@bernd-steinhauser.de>
X-Mailer: Apple Mail (2.3251)


> On 2016 Nov 10 , at 1:20 a, Bernd Steinhauser =
<linux@bernd-steinhauser.de> wrote:
>=20
> Hi,
>=20
> I'm using a program that expects a parameter (actually multiple =
parameters) in the form
> program "foo=3D'bar'"
>=20
> Because the cmdline for that program gets quite long, I wrote a =
function to call it and change parameters easily,it looks roughly like =
this:
> progfunc() {
> CORES=3D12
>    program -n ${CORES} "foo=3D'bar'" foo2=3D"1 $3"
> }
>=20
> What I would want to do is to ensure that if I call
> `progfunc x`
>=20
> this would translate into "foo=3D'x'", without touching the rest of =
the call.
> Is that somehow possible?
> iirc, variables won't work, because of the quoting style?
>=20
> Best Regards,
> Bernd

Just replace bar with a parameter default expansion.

    progfunc () {
      CORES=3D12
      program -n $CORES "foo=3D'${1:-bar}' foo2=3D"1 $3"
    }

    progfunc              # foo=3D'bar'
    progfunc "hi there"   # foo=3D'hi there'

If you don=E2=80=99t pass a first argument, bar is used. Otherwise, the =
value of the argument is.

The single quotes here don=E2=80=99t actually quote anything; they are =
literal characters included in the *double*-quoted string.

Clint=