is a key of pointed key set ? (where is the + )

is a key of pointed key set ? (where is the + )

[Marc Chantreux]

Hi all,

See this code:

pnt=h
typeset -A h
h=( k1 value )

so : 

echo ${${(P)pnt}[k1]}
prints value

but how to know if the key itself is set ? i've tried some of those
syntaxes : 

not $+{${(P)pnt}[k1]}
not ${+${(P)pnt}[k1]}

but it failed. I'm sure someone can help :)

regards


-- 
téléphone : 03.90.24.00.19
courriel  : marc.chantreux@ulpmm.u-strasbg.fr
---------------------------------------

Re: is a key of pointed key set ? (where is the + )

[Andrey Borzenkov]

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On Monday 06 November 2006 11:04, Marc Chantreux wrote:
> Hi all,
>
> See this code:
>
> pnt=h
> typeset -A h
> h=( k1 value )
>
> so :
>
> echo ${${(P)pnt}[k1]}
> prints value
>
> but how to know if the key itself is set ?

{pts/0}% typeset -A h
{pts/0}% h=(k v)
{pts/0}% print -- ${(k)h[k]+set}
set
{pts/0}% print -- ${(k)h[k1]-unset}
unset

- -andrey
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Re: is a key of pointed key set ? (where is the + )

[Marc Chantreux]

le 06/11/2006,
Andrey Borzenkov nous écrivait :
> > pnt=h
> > typeset -A h
> > h=( k1 value )
> >
> > so :
> >
> > echo ${${(P)pnt}[k1]}
> > prints value
> >
> > but how to know if the key itself is set ?
> 
> {pts/0}% typeset -A h
> {pts/0}% h=(k v)
> {pts/0}% print -- ${(k)h[k]+set}
> set
> {pts/0}% print -- ${(k)h[k1]-unset}
> unset

well .. (( $+h[k] )) does the same. You missed a part of the problem :
my associative array is "Pointed" (P). 

so we can imagine : 

[[ -n ${(k)${(P)pnt}[k1]} ]] && print "${pnt}[k1] is set"

but it doesn't work.

thanks for help 

mc 
-- 
téléphone : 03.90.24.00.19
courriel  : marc.chantreux@ulpmm.u-strasbg.fr
---------------------------------------

Re: is a key of pointed key set ? (where is the + )

[Andrey Borzenkov]

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Hash: SHA1

On Monday 06 November 2006 13:13, Marc Chantreux wrote:
> le 06/11/2006,
>
> Andrey Borzenkov nous écrivait :
> > > pnt=h
> > > typeset -A h
> > > h=( k1 value )
> > >
> > > so :
> > >
> > > echo ${${(P)pnt}[k1]}
> > > prints value
> > >
> > > but how to know if the key itself is set ?
> >
> > {pts/0}% typeset -A h
> > {pts/0}% h=(k v)
> > {pts/0}% print -- ${(k)h[k]+set}
> > set
> > {pts/0}% print -- ${(k)h[k1]-unset}
> > unset
>
> well .. (( $+h[k] )) does the same. You missed a part of the problem :
> my associative array is "Pointed" (P).
>

Somewhat kludgy but

{pts/0}% typeset -A h
{pts/0}% h=(k1 v1 k2 v2)
{pts/0}% p=h
{pts/0}% print -- ${${(Pk)p}[(r)k3]-unset}
unset
{pts/0}% print -- ${${(Pk)p}[(r)k2]+set}
set


> so we can imagine :
>
> [[ -n ${(k)${(P)pnt}[k1]} ]] && print "${pnt}[k1] is set"
>
> but it doesn't work.
>

I believe this was discussed recently. Parameter type is not propagated from 
nested substitutions, so this is not going to work. Outside of innermost 
${...} you just get list of values. Even without (P):

{pts/0}% print -- ${(k)${h}}
v1 v2
{pts/0}% print -- ${(k)${(kv)h}}
k1 v1 k2 v2

- -andrey
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Re: is a key of pointed key set ? (where is the + )

[Marc Chantreux]

Andrey Borzenkov wrote:
> Somewhat kludgy but

yes it is :) but ...

> I believe this was discussed recently. Parameter type is not propagated from 
> nested substitutions, so this is not going to work. Outside of innermost 
> ${...} you just get list of values. Even without (P):


misunderstood this point: i'll search into the archives.

regards