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boundary="------------D0zb8y7lzTs7zv8LQXGLyzf0" Message-id: <52b86cf0-d60a-438b-a32f-656c769fb672@eastlink.ca> Date: Sun, 4 Feb 2024 08:08:52 -0800 MIME-version: 1.0 User-Agent: Mozilla Thunderbird Subject: Re: for loop 'bad math expression' Content-language: en-US To: zsh-users@zsh.org References: <4c14e191-0605-4492-9f67-9a5b35ef132b@eastlink.ca> <4da0eeb4-4589-4c5d-9b89-a1a22209e18e@eastlink.ca> <7ccf5b82-a37d-47b5-a700-fb1096ab495c@eastlink.ca> <0875ffd7-e3a4-4ddc-9c4b-47e2c593ea4c@eastlink.ca> From: Ray Andrews In-reply-to: X-Seq: 29627 Archived-At: X-Loop: zsh-users@zsh.org Errors-To: zsh-users-owner@zsh.org Precedence: list Precedence: bulk Sender: zsh-users-request@zsh.org X-no-archive: yes List-Id: List-Help: , List-Subscribe: , List-Unsubscribe: , List-Post: List-Owner: List-Archive: This is a multi-part message in MIME format. --------------D0zb8y7lzTs7zv8LQXGLyzf0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit On 2024-02-03 20:20, Bart Schaefer wrote: > Note that var has NOT acquired the "-i" (integer) attribute, despite > having been assigned a number value. I noticed that myself.  I expect that all this goes back to ancient history -- arithmetic would have been an add-on at some point and integers were never robustly typed, just scalars subject to special processing, so  ' $(( )) ' says: "treat me mathematically, even tho I'm otherwise just a scalar".  But in my previous post it would seem that 'abc' IS an integer because it increments like one, but even then typeset -p shows it as scalar. It starts as a string assigned to 'var' but it would seem it gets 'promoted' to an integer variable. > --------------D0zb8y7lzTs7zv8LQXGLyzf0 Content-Type: text/html; charset=UTF-8 Content-Transfer-Encoding: 8bit

On 2024-02-03 20:20, Bart Schaefer wrote:
Note that var has NOT acquired the "-i" (integer) attribute, despite 
having been assigned a number value.
I noticed that myself.  I expect that all this goes back to ancient history -- arithmetic would have been an add-on at some point and integers were never robustly typed, just scalars subject to special processing, so  ' $(( )) ' says: "treat me mathematically, even tho I'm otherwise just a scalar".  But in my previous post it would seem that 'abc' IS an integer because it increments like one, but even then typeset -p shows it as scalar. It starts as a string assigned to 'var' but it would seem it gets 'promoted' to an integer variable.  
 

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