From: Georg Wittig <nc-wittigge@netcologne.de>
To: zsh-users@zsh.org
Subject: Global And Local Variables in zsh Functions
Date: Sun, 9 Aug 2015 00:44:57 +0200 [thread overview]
Message-ID: <55C68669.8000408@netcologne.de> (raw)
Hi,
I'm writing a zsh script that's constructing a rather complex rsync
command. One part of the script is constructing a list of exclude
commands for rsync. For this I use a global variable EXC. It is built
in the following way
EXC=''
function my_f1 () {
EXC+=" --exclude='$1'";
}
my_f1 /tmp
my_f1 /opt/windows7
echo ">>>$EXC<<<"
Function my_f1 does a lot of other things that are not relevant in
this context. The output of that script snippet is
>>> --exclude='/tmp' --exclude='/opt/windows7'<<<
which is exactly what I want.
Now I need that function my_f1 return another value that depends on
it's input parameter. So I rewrote my_f1 to my_f2 which looks as follows
EXC=''
function my_f2 () {
EXC+=" --exclude='$1'";
local x="some value depending on $1"
echo $x
}
x1=$(my_f2 /tmp)
x2=$(my_f2 /opt/windows7)
echo ">>>$EXC<<<"
To my surprise, EXC is empty now: The output is
>>><<<
Why is EXC empty in the case of my_f2, and correct in the case my_f1?
Exists there an influence of the local variable x, or is the culprit
the way that my_f2 returns it's value to the calling point? How do I
rewrite my_f2 such that the value of EXC is correct?
Thanks for your hints,
--Georg
[zsh-5.0.8-5.fc22.x86_64]
next reply other threads:[~2015-08-08 22:45 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2015-08-08 22:44 Georg Wittig [this message]
2015-08-09 0:26 ` ZyX
2015-08-09 0:31 ` Bart Schaefer
2015-08-09 0:45 ` Mikael Magnusson
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