From: Ray Andrews <rayandrews@eastlink.ca>
To: zsh-users@zsh.org
Subject: simple question regarding local variables
Date: Sat, 19 Sep 2015 09:23:53 -0700 [thread overview]
Message-ID: <55FD8C19.4050602@eastlink.ca> (raw)
In-Reply-To: <150918145300.ZM27125@torch.brasslantern.com>
I should know this:
Say several functions will use the same set of variables, so you want
some way of auto creating them for each function, *but* they must be
local to each function.
This works:
'test1' is a script:
#!/usr/bin/zsh
local variable=howdy
local anothervariable=whatever
local foo=FOO
local bar=BAR
local baz=BAZ
# and so on ... I create all my variables in the script.
'test2' is a function that sources 'test1':
test2 ()
{
varis variable
. ./test1
varis variable
}
('varis' simply prints the name and the value of variables.)
A run:
$ test2; varis variable
$variable is: ""
$variable is: "howdy"
$variable is: ""
... just as I want, sourcing 'test1' creates local variables in my
function, but why does it
work? sourcing I understand to create a child shell, thus how is it
that after 'test1'
returns, that it's local variables are known to 'test2'? Exactly as I
want, '$variable'
evaporates after 'test2' returns, so it's local. I like it, but I can't
explain it.
next prev parent reply other threads:[~2015-09-19 16:23 UTC|newest]
Thread overview: 7+ messages / expand[flat|nested] mbox.gz Atom feed top
2015-09-18 6:34 Autoload vs regular function Sebastian Gniazdowski
2015-09-18 17:15 ` Bart Schaefer
2015-09-18 18:45 ` Ray Andrews
2015-09-18 21:53 ` Bart Schaefer
2015-09-19 16:23 ` Ray Andrews [this message]
2015-09-19 16:32 ` simple question regarding local variables Bart Schaefer
2015-09-19 18:21 ` Ray Andrews
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