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Linux x86_64; rv:102.0) Gecko/20100101 Thunderbird/102.3.0 Content-language: en-US To: Zsh Users From: Ray Andrews Subject: can print but not assign to variable Content-type: text/plain; charset=UTF-8; format=flowed Content-transfer-encoding: 8bit X-Seq: 28271 Archived-At: X-Loop: zsh-users@zsh.org Errors-To: zsh-users-owner@zsh.org Precedence: list Precedence: bulk Sender: zsh-users-request@zsh.org X-no-archive: yes List-Id: List-Help: , List-Subscribe: , List-Unsubscribe: , List-Post: List-Owner: List-Archive:  $ print -l (#i)$W/rap /aWorking/Zsh/Source/Wk/RAP /aWorking/Zsh/Source/Wk/Rap /aWorking/Zsh/Source/Wk/rap $ var=(#i)$W/rap zsh: bad pattern: #i I'm not expecting trouble there.  I can make the assignment using " var=$( print ... ) ", but still it puzzles me that it's not straightforward.