Le 29/12/2017 à 09:47, Bart Schaefer a écrit :
> You're missing a semicolon after the "C". That's the reason you get 
Thank you. For some reason however, the seconde run of `export LANC=C; 
enable -r else; if true; then echo 'yep'; else echo 'nop'; fi; disable 
-r else` will return an error message with the system local anyway:

    % enable -r else;
    % export LANC=C; enable -r else; if true; then echo 'yep'; else echo
    'nop'; fi; disable -r else
    yep
    % export LANC=C; enable -r else; if true; then echo 'yep'; else echo
    'nop'; fi; disable -r else
    yep
    zsh: else: commande inconnue.

> If I understand your question, the answer is "no": you can't execute
> the front part of an "if" until the "fi" has been read.  See my
> previous email "fully parsed before executed."
I'm rather estonished by this lake of possibility to make the equivalent 
of an "\n" in the middle of a line, but OK.

So the idea would be to have something like

    % whence -w else
    else: reserved
    % enable -r else; "\n" whence -w else; if true; then echo 'yep';
    else echo 'nop'; fi; disable -r else
    else: reserved
    yep
    % whence -w else
    else: none
    % enable -r else; "\n" whence -w else; if true; then echo 'yep';
    else echo 'nop'; fi; disable -r else
    else: reserved
    yep

But "\n" doesn't work here as a substitution of an effective linefeed.
> (Well, you could switch to csh, which does execute every line as it
> goes along, even in complex structures.  But no, not in zsh.)
Nice to know, thank you.